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Arithmetic Sequence Crossed Integer Triplet Puzzle (Posted on 2022-09-21) Difficulty: 3 of 5
Determine all possible triplets (a,b,c) of positive integers, with a>b>c, such that:
  • a+bc < b+ca < c+ab are three expressions in arithmetic sequence, and:
  • a+b-c=22

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (2 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
another take; same answer | Comment 2 of 6 |
clc
for c=1:100
  for b=c+1:c+22
    a=22-(b-c);
    if a<=b
      break
    end
    if a+b*c < b+c*a && b+c*a < c+a*b  && ...
        a+b*c - (b+c*a) == b+c*a - (c+a*b)
        disp([a b c])
        disp([a+b*c , b+c*a , c+a*b])
        disp(' ')
    end
  end
end

finds

    19    10     7     [a, b, c] 
    89   143   197     [a+b*c , b+c*a , c+a*b]
 
    19    13    10     [a, b, c] 
   149   203   257     [a+b*c , b+c*a , c+a*b]
 

  Posted by Charlie on 2022-09-21 09:29:29
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