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Three Distinct Divisor Trial (Posted on 2022-10-15)

Determine the minimum value of a prime number P such that each of P-1 and P+1 has at least three distinct prime divisors.

No Solution Yet Submitted by K Sengupta

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Possible Solution

| Comment 2 of 5 |

131 is prime. 130=2*5*13, 132=2^2*3*11, satisfying the terms of the puzzle as I understand it.

Posted by broll on 2022-10-15 08:04:46

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