Think of this problem as an extension to
A four-way division.
Six friends are gathered at a pub. They have in front of them three 12-pint tankards full of beer, and an empty 5-pint mug.
Since they are still sober, they quickly calculate that they have 36 pints for the six of them, which comes to an even 6 pints per person.
How can they divide the beer equally with the containers they have available?
Note: For the purposes of the problem, assume that the pub does not have any pint glasses, and the six friends will have to drink from the four available containers.
(In reply to
re: soln by Charlie)
Thanks very much Charlie for the formatting tips. Unfortunately textpad is not available for the Mac. I tried the other idea - went into perplexus edit, attempting to modify my 1st post in this problem. I highlighted and pre-formatted, but the variable character widths have persisted. (I imagine this is "rich text")
I think the answer for me lies in cutting and posting from the right
text editor which I have yet to find. I will be experimenting with some of these soon here using my 1st post here as a test. Thanks again - SL
Edited on November 14, 2022, 9:38 pm
re(2): soln
