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Semiprimes in Arithmetic Sequence (Posted on 2022-11-20) Difficulty: 4 of 5
30 semiprimes, each less than 108, form an arithmetic sequence with strictly positive common difference.

Determine all of them.

Note: A semiprime is the product of exactly two primes.

*** For an extra challenge only, find a semi-analytic solution (simple calculator + p&p) to this puzzle.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

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solution | Comment 6 of 11 |
distance d = 1,887,270  
= 2 × 3 × 5 × 7 × 11 × 19 × 43
p = 13, p^2 - 1 = 168
1st term: 13,298,267
 1)  13298267 =      17 ×  782251
 2)  15185537 =    1109 ×   13693
 3)  17072807 =     199 ×   85793
 4)  18960077 =    4157 ×    4561
 5)  20847347 =     467 ×   44641
 6)  22734617 =     211 ×  107747
 7)  24621887 =    2267 ×   10861
 8)  26509157 =     811 ×   32687
 9)  28396427 =      37 ×  767471
10)  30283697 =      59 ×  513283
11)  32170967 =    4651 ×    6917
12)  34058237 =     263 ×  129499
13)  35945507 =      13 × 2765039
14)  37832777 =    3727 ×   10151
15)  39720047 =    2081 ×   19087
16)  41607317 =    4783 ×    8699
17)  43494587 =      23 × 1891069
18)  45381857 =      17 × 2669521
19)  47269127 =    4013 ×   11779
20)  49156397 =     101 ×  486697
21)  51043667 =     449 ×  113683
22)  52930937 =     479 ×  110503
23)  54818207 =      29 × 1890283
24)  56705477 =    7177 ×    7901
25)  58592747 =    2141 ×   27367
26)  60480017 =      13 × 4652309
27)  62367287 =     127 ×  491081
28)  64254557 =     139 ×  462263
29)  66141827 =      53 × 1247959
30)  68029097 =      31 × 2194487

I searched for an arithmetic sequence of length L=30 of semiprimes, 
all less than 10^8 using as my starting-point the constraints 
on the distance between the semiprimes, d. d cannot be odd, since 
for an odd d, a list L of no more than 3 semiprimes is possible. 
Since d is thus even, and the maximum length of such a list is 
given by p^2-1, where p is the smallest prime not a factor of d, 
d must include the prime factors of 2,3, and 5, and so be a multiple 
of 30.
I generated a list of the first 3 million primes, all < 10^8 / 2. 
I also  prepared a logical array of length 10^8, and set it 
to all false. I think using "logical" variables allowed the program to
run fast enough to make the solution possible.
By multiplying the prime list by itself, I simply set all array values 
indexed by semiprimes to true. There were about 17 million trues
or about 17% of the array. I then ran combs over this array of all 
possible d and all their possible d-1 phases where d is any
multiple of 30, from 30 to 3333330 ( ~ 10^8 / 30) and looked for 
any sequence of 30 trues in a row. It took about 18 hours of computer 
time to run. Logicals were crucial for speed because the machine was 
working using basic "and" circuits on the truth bits. E.g., I did not 
hear the familiar roar of the computer's fan working on a hard problem,
to keep the straining FPU cool - the FPU was idle! 
1.3 10^13 truth values were examined. The code is here and here

In retrospect, I could have just worried about prime factors greater than or equal to 7. That would have populated the "truth" array at a 13% rather than 17% level, but would not have sped up the checking). However, I should have limited the "phases" of the combs 

to odd numbers only, which would have cut the search time in half. 

Since the factor 2 is not present in the SPs of the solution, all relevant SPs are odd and so the sequence starts on an odd number. 


Edited on November 27, 2022, 11:40 am
  Posted by Steven Lord on 2022-11-22 13:17:14

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