The increasing sequence
1, 5, 6, 25, 26, 30, 31, 125, 126, … consists of all positive integers that can be formed by summing up distinct powers of 5 - from 1 to N presented in increasing order.
That is, 1 = 5^0, 5 = 5^1, 6 = 5^0 + 5^1, etc, etc.
What’s the 100th integer in this sequence?
100= 2^6+2^5+2^2
Then, 100 (base ten) = 1100100
Accordingly, the required 100th term is 1100020 (base5) , which is equal to:
5^6+5^5+5^2 = 18775
Edited on December 9, 2022, 7:40 am