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A quadruple gift for the N.Y. (Posted on 2022-12-28) Difficulty: 4 of 5
All answers must contain the string 2023:
1. What is the smallest number written exactly with 7 digits?
2. What is the smallest integer using 11 digits i.e. all digits 0 to 9 and an extra digit 2?
3. Write down the smallest square s.t. each digit is present at least once.
4. Evaluate the quadruplet {a,b,c,d} of distinct non-negative integers, s.t. a*b+c+d=2023 and abcd is minimal.

The 1st solver is kindly requested to post at least 2 answers out of the set of four.

See The Solution Submitted by Ady TZIDON    
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Solution solutions | Comment 1 of 8
1.    1002023 is the first such that has 2023 in it.

2.    12023456789 is the first such that has 2023 in it.


3. The smallest square s.t. each digit is present at least once is 32043^2 = 1026753849, but the smallest such that contains the string 2023 is 440684^2 = 194202387856.

from

flag=false;
for i=1:9999999
   sq=char(string(i^2));
   if  isequal(unique(sq),'0123456789')
     if flag==false || ~isempty(strfind(sq,'2023'))
      disp([char(string(i)) '  ' sq])
      flag=true;
      if ~isempty(strfind(sq,'2023'))
        break
      end
     end
   end
end

4. {a, b, c, d} = {21, 96, 0, 7} gives

21 * 96 + 0 + 7 = 2023


clearvars,clc
mn=99999999999999;
for a=1:2023
  for b=a+1:2023/a
    r=2023-a*b;
    for c=0:r
     if c~=a && c~=b 
      d=2023-a*b-c;
      if d>0 && d~=a && d~=b && d~=c
      abcd=str2double([char(string(a)) char(string(b)) ...
               char(string(c)) char(string(d)) ]);
      if abcd<mn
         mn=abcd
         mina=a
         minb=b
         minc=c
         mind=d
      end
      end
     end
    end
  end
end

... also run with a larger than b, but that results in a higher abcd concatenation.

  Posted by Charlie on 2022-12-28 08:51:38
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