There are N players in a tennis tournament. Assuming the initial pairings are done randomly, what are the odds that a certain pair will play each other?
(In reply to
answer by K Sengupta)
There are precisely N-1 matches.
The number of possible pairings is equal to : comb(N, 2) = N(N-1)/2.
Each of the possible N-1 matches have the same probability, and accordingly, it follows that the probability is equal to:
Total number of matches N-1 2
------------------------------------------ = ---------------- = -----
Total number of pairings N(N-1)/2 N
Edited on December 31, 2022, 12:31 am