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Nine points in a square crossed triangle area puzzle (Posted on 2023-02-13) Difficulty: 3 of 5
Nine points are given in a square having unit area.

Is it always possible to choose three of these points as the vertices of a triangle, such that the area of the triangle is at most 1/8?

Provide valid reasoning for your answer.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
solution via pigeon hole principle | Comment 1 of 3
Divide the unit square into four squares each with side 1/2.

With nine points and four squares at least one square will contain three points.

Those three points determine a triangle which has maximum area when each leg is 1/2. 

Area triangle <= (1/2)*bh = (1/2)*(1/2)*(1/2) = 1/8 

  Posted by xdog on 2023-02-13 19:40:07
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