A, B, and C are three consecutive integer terms (in this order) of an arithmetic sequence with nonzero common difference d.
Define:
• x = A
3+B
3+C
3
• d(x) as the
digital root of x.
Determine d(x), given that x is NOT a multiple of 3.
Let A = n-d, B = n, C=n+d
Then x = (n-d)^3 + n^3 + (n+d)^3 = 3n^3 + 6nd^2
But this makes x a multiple of 3
Have I gone wrong somewhere?