There are two identical vending machines dispensing bottled drinks. The probability of all drinks sold out at the end of a day is .25 for each automat. The probably of drinks in both machines being sold out is 0.17.
What is the probability of both machine being active by the end of the day?
P@P only.
The probability that both are active, that is, neither one is out, is 1 - (2*.25 - .17) = .67. That's because (2*.25 - .17) is the probability that one or the other or both will be out, since by inclusion/exclusion P(A or B) = P(A) + P(B) - P(A and B).
|
|
Posted by Charlie
on 2023-03-02 07:40:38 |
solution (spoiler)
