J. Weldon Wolfingham, Jr. will marry one of these women: Adrianna, Bianca, and Claire.

Some clues are furnished hereunder as follows:

1. Of Adrianna and Bianca:
• (a) Either they are both have blue eyes, or neither has blue eyes.
• (b) One has red hair and the other does not.

2. Of Adrianna and Claire:
• (a) Either they both have red hair, or neither has red hair.
• (b) One is 5'11" and the other is not.

3. Of Bianca and Claire:
• (a) One has blue eyes and the other does not.
• (b) One is 5'11" and the other is not.

4. Of the three characteristics - blue eyes, red hair and 5'11":
• (a) If any of the three women has exactly two of the three characteristics, Mr. Wolfingham will marry the one with the least number of characteristics.
• (b) If any of the three women has exactly one of the three characteristics, Mr. Wolfingham will marry the one with the greatest number of characteristics.

Who will Mr. Wolfingham marry?

Bianca is the odd one out with regards to red hair. Claire is the odd one out with regards to blue eyes and 5'11''. Bianca and Claire are different with regards to all three characteristics. By 4, there cannot be a woman with 1 characteristic and a woman with 2 characteristics. If Bianca has 1 characteristic, then Claire has 2 characteristics. If Bianca has 2 characteristics, then Claire has 1 characteristic. Therefore, Bianca either has 0 or 3 characteristics. If Bianca has 0 characteristics, then Claire has 3 characteristics. Then, Adrianna has just red hair. Since she has 1 characteristic, Mr. Wolfingham will marry the woman with the most characteristics, which is Claire. If Bianca has 3 characteristics, then Claire has 0 characteristics. Then, Adrianna has blue eyes and is 5'11''. Since she has 2 characteristics, Mr. Wolfingham will marry the woman with the least characteristics, which is Claire. Therefore, he will marry Claire.

Posted by Math Man on 2023-03-04 18:04:36