All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Probability
6 teams (Posted on 2023-03-17) Difficulty: 4 of 5
6 football teams each of different level of play compete in a knockout fashion: the 1st pair chosen at random and in the following rounds the winner is facing another randomly chosen team. Given that a certain team won three games so-far what is the probability of winning the 4th game?

No Solution Yet Submitted by Ady TZIDON    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
re: an ambiguity? | Comment 3 of 11 |
(In reply to an ambiguity? by Steven Lord)

Initially I had the same worry about the ambiguity. I wrote my solution on the assumption that the player's first game was indeed the first game of the whole tournament.


My second thought was Does it matter? Just ignore the first game. But then he'd be playing against a proven winner, of at least one game. That would need to be taken into consideration.

The remaining paragraph was removed, as it was completely wrong.


Edited on March 17, 2023, 10:41 am
  Posted by Charlie on 2023-03-17 10:30:06

Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (0)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information