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Arithmetic Progression Triangle (Posted on 2007-01-28) Difficulty: 3 of 5
Given lengths R and r with R > 2r. Construct a triangle with side lengths in arithmetic progression and R and r its circumradius and inradius respectively.

See The Solution Submitted by Bractals    
Rating: 2.5000 (2 votes)

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Puzzle Thoughts Comment 6 of 6 |
 The three sides of the triangle are: 
√(4r(2R-r))-√(2r(R-2r))
√(4r(2R-r))
√(4r(2R-r))+√(2r(R-2r))
 

Edited on March 17, 2023, 1:15 pm
  Posted by K Sengupta on 2023-03-17 13:13:54

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