Find all ten digit numbers each containing the digit from 0 to 9 once and only once, with the property that the successive pairs of digits from left to right are divisible by 2,3,4,5,6,7,8,9 and 10.

[In other words: The two-digit number formed with the 'N'th digit and the '(N+1)'st digit is divisible by '(N+1)', where N = 1,2,3,4,....,9].

Edited on April 19, 2023, 10:26 pm

Posted by K Sengupta on 2023-04-19 22:25:38