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Quick estimate (Posted on 2023-05-24) Difficulty: 2 of 5
This puzzle of mine will enable to test your ingenuity in solving problems quickly, applying all your previous experience to get the correct answer in minimal time.

Start your timer. Imagine being interviewed for a job of your best dreams.
The letters in the equation below represent POSITIVE INTEGERS.

You are asked to provide the value of t as accurate as possible.

Free to use brains, paper, calculator, friends...

Given: t^2=Sqrt(116^m+611^n+225^q)

Your answer:
Stop the timer.
Time spent:.

Your comments:

No Solution Yet Submitted by Ady TZIDON    
Rating: 1.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Solution re: Not the solution -- maybe it still is | Comment 2 of 11 |
(In reply to Not the solution by Charlie)

Repeating


116 = 2^2 * 29
611 = 13 * 47
225 = 3^2 * 5^2

If, for example, m were made to be 2^2 * 29^3 * 13^4 * 47^4 * 3^3 * 5^4, and likewise, each of the others were made so the entire term were each of the prime factors, other than 3 were present to the 4th power, except the 3 to the third power, when added together that would still be the number as stated in the "not the solution". It's just that the values of m, n and q would be larger. It would still result in the same t: 531570. Each term (including both coefficient and variable) would be the same, and there being three of them, the 3 would get the change from 3rd power to 4th.

Edited on May 24, 2023, 11:40 am
  Posted by Charlie on 2023-05-24 11:36:25

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