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Consecutive inequality (Posted on 2023-07-24)

Let x, y and z be consecutive integers such that

1/x+1/y+1/z>1/45

Find the maximum value of x+y+z.

No Solution Yet Submitted by Danish Ahmed Khan

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Puzzle Answer

Comment 3 of 3 |

The required maximum value of x+y+z is 405.

Posted by K Sengupta on 2023-07-24 23:18:50

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