Determine as many positive integers, N, not ending in 0, as you can, such that N^5 contains two copies of N.
9^5=59049
99^5=9509900499
999^5=995009990004999
9999^5=99950009999000049999
99999^5=9999500009999900000499999
...
Therefore, the answers are 9, 99, 999, 9999, 99999, ...
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Posted by Math Man
on 2023-09-24 13:33:51 |