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Sixth powers (Posted on 2023-10-16) Difficulty: 2 of 5
Provide all solutions of x6=(x-1)6.

Source: Cyprus’s Math. Competition

No Solution Yet Submitted by Ady TZIDON    
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Solution Solution Comment 2 of 2 |
I could expand things out and brute force it, as in Larry's solution; but there's a more elegant way.

Let w=1/2+i*sqrt(3)/2, the principal complex 6th root of unity.

Now take the 6th root of each side, and on the left side I'll iterate through the powers of w.  Let p=0 to 5.

Then w^p*x = x-1.  And solve for x we get x=1/(1-w^p).

Then substituting in the values of p we get the solution set
{1/(1-w^0), 1/(1-w^1), 1/(1-w^2), 1/(1-w^3), 1/(1-w^4), 1/(1-w^5)}

Note the first member is division by 0, so must be discarded.  Then simplify the rest to get 
x = {1/(1/2-i*sqrt(3)/2), 1/(3/2-i*sqrt(3)/2), 1/2, 1/(1/2+i*sqrt(3)/2), 1/(3/2+i*sqrt(3)/2)}
x = {1/2+i*sqrt(3)/2, 1/2+i*sqrt(3)/6, 1/2, 1/2-i*sqrt(3)/6, 1/2-i*sqrt(3)/6}.

  Posted by Brian Smith on 2023-10-16 23:19:42
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