perplexus.info :: Numbers : Squares and Cubes II

Squares and Cubes II (Posted on 2013-05-17)

5 consecutive positive integers are given such that the sum of the middle 3 numbers is a perfect square, and the sum of all 5 numbers is a perfect cube. What is the minimum possible value of the first integer?

No Solution Yet Submitted by Danish Ahmed Khan

Rating: 3.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)

Puzzle Answer

Comment 2 of 2 |

The required five consecutive positive integers are: 673, 674, 675, 676, and 677.

Posted by K Sengupta on 2023-12-17 22:03:49

Please log in:

Login:
Password:
Remember me:

Sign up! \| Forgot password

Search:

Search body:

Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (0)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:


perplexus dot info