Given that:
22022 - 31*22014 + 2n is a perfect square for certain positive integer n
Find the value of n
Factor: 2^2014 * (2^8 - 1) + 2^n = 2^2014 * (225) + 2^n = K^2
Rearrange: 2^n = (K + 15*2^1007) * (K - 15*2^1007)
Each factor is a power of 2, say 2^a and 2^b where n = a+b.
Set equivalent and subtract:
2^a - 2^b = 30*(2^1007) = 15*(2^1008) = (2^4 - 1)*(2^1008) = 2^1012 - 2^1008
and n = 1012+1008 = 2020.
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Posted by xdog
on 2023-12-23 18:55:01 |