If a, b, c, and d are real numbers, then find a, b, c, and d.
a + 1/b = 1
b + 1/c = 2
c + 1/d = 3
d + 1/a = 4
Modification of a problem seen on SyberMath's youtube channel
By straightforward substitutions:
B=1/(1-A)
D=4-1/A
C=3-1/D=3-1/(4-1/A)
B=2-1/C=2-1/(3-1/D)=2-1/(3-1/(4-1/A))
1/(1-A)=2-1/(3-1/(4-1/A))
(1-A)/(1-2A)=3-1/(4-1/A)
(2-5A)/(1-2A)=1/(4-1/A)
(1-2A)=(4-1/A)(2-5A)
A-2A^2=(4-A)(2-5A)
18A^2-12A+2=0
A=1/3
B=3/2
C=2
D=1
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Posted by Jer
on 2024-01-17 13:48:24 |