Suppose 2
2022 - 31*2
2014 + 2
n is a perfect square for a certain positive integer value of n.
Find the value of n.
Simplify to 225*2^2014 + 2^n = x^2
The easy option is to assume n>2014, then some factoring gets us to (2^1007)^2 * (225+2^(n-2014)) = x^2
Then all we need is 225+2^(n-2014) to be a perfect square. This happens at n-2014=6, from 225+2^6=17^2
Then the answer is n=2020.