a. What is the probability that a randomly chosen leap year has 53 Fridays?
b. What is the probability of having 53 Fridays in a leap year
of the current century?
Rem: Gregorian calendar, years from 1600 till 2099
(In reply to
solution by Charlie)
The problem asks for 1600-2099, but that is not a Gregorian cycle. A Gregorian cycle has 400 years, so it is like 1600-1999 or 1700-2099. The probability of a leap year having 53 Fridays in that cycle is 28/97=0.2886597938... Therefore, we have the following possible answers.
a. Julian calendar:2/7=0.2857142857...
Gregorian calendar:28/97=0.2886597938...
1600-2099:35/122=0.2868852459...
b. 2000-2099:7/25=0.28
2001-2100:7/24=0.2916666666...
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Posted by Math Man
on 2024-02-29 12:14:01 |
re: solution
