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Equilateral triangle by distances (Posted on 2024-03-29) Difficulty: 3 of 5
The three vertices of an equilateral triangle are at distances 1, 2, and 3 from a line.

Find all possible areas of this triangle.

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Solution computer solution | Comment 1 of 5
Using Geometer's Sketchpad, when the distance-2 vertex is the sole point on its side of the line the area is about 10.9, but if the distance-3 is the isolated vertex the area is about 12.0. If the distance-1 vertex is the one isolated, the area is about 6.93 or 7,5 depending on the construction.

(The 6.93 is spurious; see below).

If all are on the same side, I get 1.73 as the area.

I suspect the other cases have alternatives also, but it's hard to see the appropriate construction.  (again, see below -- the Matlab calculation)

Matlab calculation:

syms x1 x2 x3
for y1=[1 -1]
  for y2=[2 -2]
    for y3=[3 -3]
     x  = vpasolve([(x1-x2)^2+(y1-y2)^2==(x2-x3)^2+(y2-y3)^2, ...
       (x1-x2)^2+(y1-y2)^2==(x1-x3)^2+(y1-y3)^2, ...
       abs(atand((y3-y1)/(x3-x1))-atand((y2-y1)/(x2-x1)))==60], ...
       [x1,x2,x3]);  
     if ~isempty(x.x1)
       fprintf('(%9.6f,%2d) (%9.6f,%2d) (%9.6f,%2d)  %9.6f %9.6f ', ...
            x.x1,y1,x.x2,y2,x.x3,y3, ...
            (sqrt(3)/4)*((x.x1-x.x2)^2+(y1-y2)^2), ...
            (sqrt(3)/4)*((x.x1-x.x3)^2+(y1-y3)^2))
     end
    end
  end
end

finds

               vertices                             area based on
                                                  side 1     side 2
(-40.716919, 1) (-45.913071, 2) (-44.181020,-3)  12.124356 12.124356
(-25.356636, 1) (-21.315184,-2) (-20.737834, 3)  10.969655 10.969655
(-25.356636,-1) (-21.315184, 2) (-20.737834,-3)  10.969655 10.969655
(-40.716919,-1) (-45.913071,-2) (-44.181020, 3)  12.124356 12.124356

which seem to be the 10.9 and 12.1 found via GSP. The limitation would be arising from looking for a difference of 60.

Changing the sought difference in angles to 120° gives

(-43.026320, 1) (-45.913071,-2) (-41.871619,-3)   7.505553  7.505553
(-43.026320,-1) (-45.913071, 2) (-41.871619, 3)   7.505553  7.505553

which is the 7.5 found by GSP.

specifying "digits 10" before doing the vpasolve gives, when looking for 60°,

(-38.802870, 1) (-37.070819, 2) (-38.802870, 3)   1.732051  1.732051
(-40.716919, 1) (-45.913071, 2) (-44.181020,-3)  12.124356 12.124356
(-25.356636, 1) (-21.315184,-2) (-20.737834, 3)  10.969655 10.969655
(-25.356636,-1) (-21.315184, 2) (-20.737834,-3)  10.969655 10.969655
(-40.716919,-1) (-45.913071,-2) (-44.181020, 3)  12.124356 12.124356
(-38.802870,-1) (-37.070819,-2) (-38.802870,-3)   1.732051  1.732051

now finding the 1.7 solution from GSP.

Using angle difference of 120° with digits 10:

(-43.026320, 1) (-44.758370, 2) (-43.026320, 3)   1.732051  1.732051
(-43.026320, 1) (-45.913071,-2) (-41.871619,-3)   7.505554  7.505553
(-43.026320,-1) (-45.913071, 2) (-41.871619, 3)   7.505554  7.505553
(-43.026320,-1) (-44.758370,-2) (-43.026320,-3)   1.732051  1.732051

The Matlab program has found

1.732051
7.505553
10.969655
12.124356

What about GSP's  6.93?

Going back, I see that I mishandled the case where the area was 6.93. I confused two lines and the distances of the vertices from the line were 1, 1, and 3 rather than 1, 2 and 3.

Edited on March 29, 2024, 1:31 pm
  Posted by Charlie on 2024-03-29 13:30:11

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