All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Numbers
Divisible by Length (Posted on 2024-04-27) Difficulty: 3 of 5
Determine the largest integer A such that for K=1,2,3,...,length(A) the first K digits of A form an integer divisible by K.
For example, for 56165, 5 is divisible by 1, 56 is divisible by 2, 561 is divisible by 3, 5616 is divisible by 4 and 56165 is divisible by 5.

See The Solution Submitted by K Sengupta    
Rating: 5.0000 (1 votes)

Comments: ( Back to comment list | You must be logged in to post comments.)
Comparison to expectation | Comment 3 of 6 |
(In reply to Solution by Larry)

A simple formula for the number of length A numbers is n(A)=(10^A)/(A!)

The numbers underperform expectation for all n up to n(14)=1147.07
after that, there are more numbers than predicted from n(15)=764.72
through n(25)=0.64

n(26)=0.25 was large enough that I'd hoped maybe there might just be one before seeing the previous posts.  

  Posted by Jer on 2024-04-28 10:23:17
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information