Find the smallest integer N such that N+1 is a prime, N+2 is the product of 2 primes, N+3 is the product of 3 primes, N+4 is the product of 4 primes and N+5 is the product of 5 primes.
(In reply to
computer solution by Charlie)
The factorization for 15123, 15124, and 15125 are:
15123 = 3x71x71
15124 = 2x2x19x199
15125 = 5x5x5x11x11
Can a solution be found whereby all the four numbers can be expressed as product of distinct prime numbers?
re: computer solution
