The diameter of the circle (O), (XY) is 12cm.

Two adjacent vertices of the square (ABCD) lie on the diameter of that circle, while the other two vertices lie on the circumference of the circle.

What is the length of a diagonal of this square (DB)?

Form a rectangular triangle of sides L, L/2 and an hypotenusa of R (in this case 6cm). With this triangle use the Pitagoras theorem and obtain L.
It gives L=12/√5
So, because it is a square, every side is equal, to obtain the diagonal you simply multiply L*√2=12*√2/√5=7.58946638437

Posted by Antonio on 2003-08-22 03:11:55