A traditional soccer ball has 20 regular (spherical) hexagons with 12 regular pentagons situated so each is surrounded by five of the hexagons.
Given such a ball that's 22 cm in diameter, what is the arc length of one side where two polygons meet (penta/hexa or hexa/hexa) in centimeters?
(In reply to
re: Solution by Charlie)
I don't see why not. It's my solution so the burden of proof is on me, but can you give a counterexample?
If we took a 3-4-5 triangle and puffed it into a 12/pi diameter circle wouldn't the arcs be 1/4, 1/3, 5/12? Does it work differently in 3d?
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Posted by Jer
on 2024-06-29 14:40:57 |
re(2): Solution
