A traditional soccer ball has 20 regular (spherical) hexagons with 12 regular pentagons situated so each is surrounded by five of the hexagons.
Given such a ball that's 22 cm in diameter, what is the arc length of one side where two polygons meet (penta/hexa or hexa/hexa) in centimeters?
(In reply to
re(2): Solution by Jer)
I picture the triangle and its circumcircle as the result of puffing out the triangle. The three vertices are fixed points.
Then the 5 side of the 3-4-5 triangle is half of the circumference, instead of the proportionate 5/12.
re(3): Solution
