Determine all pairs (x,y) of positive integers that satisfy this equation:
x3+y3= x2+42xy+y2
Special case: suppose x=y
Then 2x^3 = 44x^2
2x^2(x - 22) = 0
which give 2 solutions, although (0,0) is disallowed since x,y > 0.
But we have one solution: (22,22)
Then by brute force (but not analytically so far),
I also found (1,7) and (7,1).
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Posted by Larry
on 2024-07-01 09:27:54 |