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Directronix Determination (Posted on 2024-07-28) Difficulty: 3 of 5
The points equidistant from (0, 0) and (1, 1) form the perpendicular bisector of the segment joining the given points, which has the equation x + y = 1.
The distance from a point to a line or curve is defined as the shortest distance.
Call the equidistant point (x, y) and the closest point on the curve (a, b).

a) The set (locus) of points equidistant from (0, 0) and the line x + y = 1 forms a familiar shape.
Name the shape, and find its equation.(as a relation between x and y or as parametric equations of a)

b) Determine the locus of points equidistant from the origin and the hyperbola x y = 1, x > 0. (as a relation between x and y or as param. eqns of a)

c) Find the locus of points equidistant from the origin and the circle through (1, 1) that's tangent to both axes. (in {x, y} or a form)

Show your steps and reasoning.

No Solution Yet Submitted by K Sengupta    
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Solution part c) Comment 3 of 3 |
https://www.desmos.com/calculator/6wucxzlv9b

I'm not going to type in all the equations, they are all on the Desmos graph. 

Eq 4 is the derivative (had to use calculus)
Eq 5 is the point on the circle for a given k
Eq 8 is perpendicular to the circle
Eq10 is the perpendicular bisection
Eqs 8 and 10 must cross

the next few are just the algebra to solving the system

Eq16 is the points of the locus in terms of k.
Eq17 is the parametric equations of the locus.

  Posted by Jer on 2024-07-29 10:50:08
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