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Sphere intersection (Posted on 2024-10-04) Difficulty: 3 of 5
Sphere (x+2)2+(y+3)2+(z+2)2=25 and (x+2)2+(y+3)2+(z-4)2=16 intersect at a circle.

What is the radius of this circle of contact?

No Solution Yet Submitted by Danish Ahmed Khan    
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Puzzle Thoughts | Comment 2 of 3 |
The required radius of the intersecting circle is =~ 3.307189
  Posted by K Sengupta on 2024-10-05 07:56:15
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