perplexus.info :: Numbers : An Exponential and Diophantine Puzzle

An Exponential and Diophantine Puzzle (Posted on 2024-11-01)

Solve in non-negative integers

7^y + 2 = 3^x

No Solution Yet Submitted by K Sengupta

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Well ...

Comment 1 of 1

Two solutions are seen by inspection:

(x,y) can be (1,0) or (2,1)

7^0 + 2 = 3^1

7^1 + 2 = 3^2

But a proof that there are no other solutions escapes me.

Posted by Larry on 2024-11-01 12:32:20

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