Determine the number of five digit integers 37ABC, such that 37ABC, 37BCA, 37CAB is divisible by 37.
The choice of 37ABC instead of ABC was so that a digit can be zero.
Of the 27 multiples of 37 under 1000, ALL of them work!
037, 370, 703
074, 740, 407
111,111,111 etc...
I wrote them all down before noticing.
I never knew this fact (I haven't proved it yet) but the answer is 27.
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Posted by Jer
on 2024-11-20 10:37:47 |