Let x=202420252026. Then, x^2-(2*(x+1)^2)+(x+2)^2=x^2-(2*(x^2+2x+1))+(x^2+4x+4)=x^2-2x^2-4x-2+x^2+4x+4=2.
This year is a square year 45^2=2025. This puzzle involves squares of numbers with years near 2025. Interestingly, the pid of this puzzle is a square, 120^2=14400.
Squares
