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Factorial Product Poser (Posted on 2025-02-27)

Determine all possible pairs (x, y) of nonnegative integers that satisfy this equation:

x!=120*(y!)

Prove that there are no further pairs in consonance with the given conditions.

No Solution Yet Submitted by K Sengupta

Rating: 5.0000 (1 votes)

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re(2): More solutions

| Comment 4 of 5 |

(In reply to re: More solutions by Charlie)

Maybe, the reason you missed them was because Jer said that 5!=210 and 4*5*6=129. He should have said that 5!=120 and 4*5*6=120.

Posted by Math Man on 2025-03-01 20:43:26

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