The trapezoid ABCD of bases AB and CD, has angle A = 90 degrees, AB = 6, CD = 3 and AD = 4. Let E, G, H be the circumcenters of triangles ABC, ACD, ABD, respectively. Find the area of the triangle EGH.
Let F be the midpoint of AB.
The trapezoid is then composed of three 3-4-5 right triangles: CDA, AFC, BFC.
G is the midpoint of AC, H is the midpoint of BD. These points are midway between the trapezoid bases and 3/2 units apart.
E is on line FC (as is H) a distance 7/8 from F. EH=9/8
Thus triangle EGH is a right triangle with area (1/2)(3/2)(9/8)=27/32
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Posted by Jer
on 2025-03-11 12:11:38 |