y=2x^2+a
x= 2y^2+b

intersect at four distinct points.
These four points are on the same circle of area 10.

Given that a, b < 0, determine the minimum value of ab.

I assumed that the other values for a,b referred to the other points of intersection. As far as I can tell, the circle is fixed.

Posted by broll on 2025-03-14 12:01:15