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Six Digit Transformation Problem (Posted on 2025-03-24) Difficulty: 3 of 5
The first digit of the six digit number 1abcde is 1.

If the first digit is moved to the last place, we get a new number abcde1.

Given that, abcde1:1abcde = 7:2, find the value of abcde.

No Solution Yet Submitted by K Sengupta    
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Solution Analytic solution; and program | Comment 3 of 4 |
abcde1/1abcde = 7/2
2 * abcde1 = 7 * 1abcde
 lhs ends in 2 so 7*e must end in 2.  
 Therefore e = 6

2 * abcd61 = 7 * 1abcd6
 lhs ends in 22 so 7 * d6 must end in 22
  Therefore d=4

2 * abc461 = 7 * 1abc46
 lhs ends in 922 so 7 * c46 must end in 922
  Therefore c=8

2 * ab8461 = 7 * 1ab846
 lhs ends in 6922 so 7 * b846 must end in 6922
  Therefore b=3

2 * a38461 = 7 * 1a3846
 lhs ends in 76922 so 7 * a3846 must end in 76922
  Therefore a=5

abcde is 53846

153846 * 3.5 = 538461

confirmed by a program
----------------------
digits = '0123456789'

for a in digits:
    for b in digits:
        for c in digits:
            for d in digits:
                for e in digits:
                    x = 100000 + int(a+b+c+d+e)
                    y = 10*int(a+b+c+d+e) +1
                    if y/x != 3.5:
                        continue
                    print(x,y)


  Posted by Larry on 2025-03-24 15:50:07
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