Playing with a full precision calculator https://www.mathsisfun.com/calculator-precision.html
The number with 3 3's is divisible by 3^2
The number with 9 3's is divisible by 3^3
The number with 27 3's is divisible by 3^4
The number with 81 3's is divisible by 3^5
The number with 243 3's is divisible by 3^6
The number with 729 3's is divisible by 3^7
The number with 3^7 3's is divisible by 3^8
From which I conjecture
The number with (3^n) 3's is divisible by 3^(n+1)
Our number has 3^2013 3's so my conjecture is it's divisible by 3^2104.
So my answer is 2014
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Posted by Jer
on 2025-05-17 17:24:56 |
my conjecture
