All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes > Geometry
Parallelogram extension (Posted on 2025-05-31) Difficulty: 3 of 5
If a square is drawn externally on each side of a parallelogram, prove that:

(a) The quadrilateral formed by the centers of these squares is also a square.

(b) The diagonals of the new square formed are concurrent with the diagonals of the original parallelogram.

No Solution Yet Submitted by Danish Ahmed Khan    
No Rating

Comments: ( Back to comment list | You must be logged in to post comments.)
Some Thoughts Possible Solution Comment 1 of 1
The deckchair principle.

part (a)

The problem becomes trivial if the parallelogram is a rectangle.

As the rectangle collapses into a parallelogram, like a folding deckchair, 'something' happens to one side of the new quarilateral (i.e. the square). Let's assume wlog it gets shorter. 

But that side is the distance between the centre of a large square and the centre of a small square, so whatever happened to that side must by symmetry also have happened to the other 3 identical sides which are also the distances between the centre of a large square and the centre of a small square.

So the quadrilateral remains a square.

Similarly, when the parallelogram is a rectangle, the required diagonals are trivially concurrent. As the rectangle collapses into a parallelogram, it remains a square as shown above,  so its diagonals continue to meet at the same point as those of the parallelogram.



  Posted by broll on 2025-06-01 01:33:53
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (5)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2025 by Animus Pactum Consulting. All rights reserved. Privacy Information