Two points, A and B, are on the Cartesian plane at (-1,4) and (9,6).

A. What point on the x-axis is equidistant from each of these two points?

B. What point on the y-axis is equidistant from these two points?

In my last solution comment, I posted a wrong distance in Y in order to find an equidistant point in the y-axis. From the y-axis, form two right angle triangles, one with sides 1, Y and an hypotenusa of M, the other right angle triangle with sides Y, 9 and an hipoteniusa of M. We get an equation M²=M²=1+4+4*Y*Y²=Y²+81. This will give us Y=19. We sum 4+2+19=25.
So from the origin in the y-axis the point would be in (0,25)

Posted by Antonio on 2003-09-03 10:24:00