Find a number
ABCDEFGHIJ such that
A is the count of how many 0's are in the number,
B is the number of 1's, and so on.
(Taken from http://einstein.et.tudelft.nl/~arlet/puzzles/logic.html)
It looks like the last paragraph of my solution was cut off even though it accepted the post, so this is my concluding paragraph:
So the number must be 6BC0001000, with B at least 1 and C no greater than 1. Neither B and C can be 0, since there are already six 0's. So C must be 1, making B a 2, and giving the number 6210001000.
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Posted by Ender
on 2002-07-11 04:58:19 |
Exactly one solution (continued)
