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This Way and That Way (Posted on 2003-11-09) Difficulty: 3 of 5
ABCDE * 4 = EDCBA. Solve for A,B,C,D, and E where each is a unique integer that can take any value from 0 to 9.

See The Solution Submitted by Ravi Raja    
Rating: 3.4000 (5 votes)

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this one is easy | Comment 9 of 12 |
as long as one of the letters stands for 0 they will multiply out to equal 9
e.g. 0*1*2*3*9*4=0
and
9*3*2*1*0=0

the problem is solved
  Posted by todd on 2003-11-13 18:41:06
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