Prove that if you draw a right triangle and then draw a circle with its center on the hypotenuse's midpoint such that it intersects at least 1 vertex, it will in fact intersect all three.
(In reply to
solution by SilverKnight)
This is probably redundant, but in case it isn't clear what isosceles triangles I'm referring to in the previous comment....
One triangle is made up of:
hypotenuse midpoint (X/2, Y/2),
one vertex (X,0), and
the origin (0,0)
with both equal sides (X/2, Y/2)-(0,0) AND (X/2, Y/2)-(X,0)
The other triangle is made up of:
hypotenuse midpoint (X/2, Y/2),
one vertex (0,Y), and
the origin (0,0)
with both equal sides (X/2, Y/2)-(0,0) AND (X/2, Y/2)-(0,Y)
re: solution
