All about flooble | fun stuff | Get a free chatterbox | Free JavaScript | Avatars    
perplexus dot info

Home > Shapes
Two Square Settlement (Posted on 2016-02-09) Difficulty: 2 of 5
Each of the sides of square PQRS has length 1.
Points E and F are on QR and RS, respectively, so that triangle PEF is equilateral.
A square with vertex Q has sides that are parallel to those of PQRS and a vertex on PE.
The length of a side of this smaller square is (x –√y)/z , where x, y, and z are positive integers and y is not divisible by the square of any prime.

Determine x,y and z

  Submitted by K Sengupta    
Rating: 5.0000 (1 votes)
Solution: (Hide)
(x,y,z)=(3,3,6)

For an explanation, refer to the solution submitted by Jer in this location.

Comments: ( You must be logged in to post comments.)
  Subject Author Date
SolutionSolutionJer2016-02-10 11:58:01
Please log in:
Login:
Password:
Remember me:
Sign up! | Forgot password


Search:
Search body:
Forums (1)
Newest Problems
Random Problem
FAQ | About This Site
Site Statistics
New Comments (6)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On

Chatterbox:
Copyright © 2002 - 2024 by Animus Pactum Consulting. All rights reserved. Privacy Information