All about
flooble
|
fun stuff
|
Get a free chatterbox
|
Free JavaScript
|
Avatars
perplexus
dot
info
Home
>
Numbers
3 multiples of cubes (
Posted on 2017-10-24
)
What are the 3 consecutive integers - such that each is divisible by a cube (other than 1^3)?
Provide the triplet of smallest numbers.
Submitted by
Ady TZIDON
No Rating
Solution:
(
Hide
)
The smallest triplet:
1375 = 5^3 * 11 ;
1376 = 2^3 * 172 ;
1377 = 3^3 * 51
Comments: (
You must be logged in to post comments.
)
Subject
Author
Date
computer solution
Charlie
2017-10-24 11:06:36
Please log in:
Login:
Password:
Remember me:
Sign up!
|
Forgot password
Search:
Search body:
Forums (0)
Newest Problems
Random Problem
FAQ
|
About This Site
Site Statistics
New Comments (3)
Unsolved Problems
Top Rated Problems
This month's top
Most Commented On
Chatterbox:
blackjack
flooble's webmaster puzzle
Copyright © 2002 - 2024 by
Animus Pactum Consulting
. All rights reserved.
Privacy Information