If there were zero zeros in a row, then N would be 1/1.11 = 0.9009009009009008
If there was one zero in a row, then N would be 1/1.0101 = 0.99000099000099
So with groups of 50 zeros as above,
N is a repeating pattern of 51 9s and followed by 102 0s
For an explanation, refer to the solution submitted by Charlie in this location.
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