Two Packs Of Cards (Posted on 2004-02-05)

	Submitted by Ravi Raja
Rating: 3.8571 (7 votes)
Solution:	(Hide)
There are two cases to be considered. CASE 1 : King of Hearts is drawn from Pack A and shuffled with Pack B Probability of drawing King of Hearts from Pack A = 1/51 (as Queen of Hearts is not to be drawn) Probability of having King of Hearts on the top of the Pack B = 2/53 So total probability of case 1 = (1/51) * (2/53) = 2 / (51 * 53) CASE 2 : King of Hearts is not drawn from Pack A Probability of not drawing King of Hearts from Pack A = 50/51 (as Queen of Hearts is not to be drawn) Probability of having King of Hearts on the top of the Pack B = 1/53 So total probability of case 2 = (50/51) * (1/53) = 50 / (51 * 53) Now adding both the probability, the required probability is = 2 / (51 * 53) + 50 / (51 * 53) = 52 / (51 * 53) = 52 / 2703 = 0.0192378

	Subject	Author	Date
	Testbanks21	robin smithsters	2022-04-20 07:46:08
	Puzzle Solution	K Sengupta	2021-12-31 06:14:41
	A KING INDEED	G	2004-02-06 20:16:53
	re(2): Agreement with nobody	Phil	2004-02-06 14:42:25
	re: Agreement with nobody	Charlie	2004-02-06 14:20:34
	Agreement with nobody	Phil	2004-02-06 13:45:34
	solution	Freddy Grants	2004-02-05 23:48:21
	re(4): Solution	Phil	2004-02-05 23:28:55
	re(3): Solution	winnifred foster	2004-02-05 17:37:36
	Agreement with Charlie	Phil	2004-02-05 15:09:48
	my solution	Ady TZIDON	2004-02-05 13:55:43
	re(2): Solution	lovejoy	2004-02-05 11:46:33
	Solution	Brian Smith	2004-02-05 09:09:12
	re: Solution	winnifred foster	2004-02-05 08:45:02
	re: Solution	Charlie	2004-02-05 08:43:55
	Solution	stan	2004-02-05 08:30:09