perplexus.info :: Numbers : N and N^5

N and N^5 (Posted on 2023-09-19)

Determine as many positive integers, N, not ending in 0, as you can, such that N^5 contains two copies of N.

Submitted by K Sengupta

Rating: 5.0000 (1 votes)

Solution: (Hide)

{9,99,999, 9999,99999, ... } appears to be the solution set, since:
9^5=59049 99^5=9509900499 999^5=995009990004999 9999^5=99950009999000049999 99999^5=9999500009999900000499999 ...
For an explanation, refer to the solution submitted by Larry in this location.

Comments: ( You must be logged in to post comments.)

Subject	Author	Date
Answer	Math Man	2023-09-24 13:33:51
solution	Larry	2023-09-19 12:06:33

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